wen 19道Python列表和元祖的练习题
1.创建一个空列表,命名为names,往里面添加old_driver,rain,jack,shanshan,peiqi,black_girl元素
names = ["old_driver","rain","jack","shanshan","peiqi","black_girl"]
print(names)
2.往names列表里black_girl前面插入一个alex
names.insert(names.index("black_girl"),"alex")
print(names)
3.把shanshan的名字改成中文，张三
names[names.index("zhangsan")] = "张三"
print(names)
4.往names列表里rain的后面插入一个子列表，[“oldboy”,”oldgirl”]
names.insert(names.index("rain")+1,["oldboy","oldgirl"])
print(names)
5.返回peiqi的索引值
print(names.index("peiqi"))
6.创建新列表[1,2,3,4,2,5,6,2],合并入names列表
names.extend([1,2,3,4,2,5,6,2])
print(names)
7.取出names列表中索引4-7的元素
print(names[4:7])
8.取出names列表中索引2-10的元素,步长为2
print(names[2:10:2])
9.取出names列表中最后3个元素
print(names[-3:])
10.循环names列表，打印每个元素的索引值，和元素
枚举
for index,name in enumerate(names):
print("%s. %s" % (index,name))
计数
index = 0
for name in names:
print("%s. %s" % (index, name))
index += 1
11.循环names列表，打印每个元素的索引值，和元素,当索引值为偶数时，把对应的元素改为-1
for index,name in enumerate(names):
if index % 2 == 0:
names[index] = -1
print(names)
12.names里有3个2，请返回第2个2的索引值。不要人肉数，要动态找（提示，找到第一个2的位置，在次基础上再找第2个）
print(names.index(2,names.index(2)+1))
13.查找列表(或元祖或字典)中元素，移除每个元素的空格，并查找以 a 或 A 开头 并且以 c 结尾的所有元素
li = ["alec", " aric", "Alex", "Tony", "rain"]
tu = ("alec", " aric", "Alex", "Tony", "rain")
dic = {"k1": "alex", "k2": " aric","k3": "Alex", "k4": "Tony"}
li = ["alec", " aric", "Alex", "Tony", "rain"]
for S in li:
S = S.strip()
prefix_a = S.startswith("a")
prefix_A = S.startswith("A")
suffix_c = S.endswith("c")
if prefix_a or prefix_A and suffix_c:
print("要查找的元素:%s" % S)
tu = ("alec", " aric", "Alex", "Tony", "rain")
for S in tu:
S = S.strip()
prefix_a = S.startswith("a")
prefix_A = S.startswith("A")
suffix_c = S.endswith("c")
if prefix_a or prefix_A and suffix_c:
print("要查找的元素:%s" % S)
dic = {"k1": "alex", "k2": " aric","k3": "Alex", "k4": "Tony"}
for S in dic.values():
S = S.strip()
prefix_a = S.startswith("a")
prefix_A = S.startswith("A")
suffix_c = S.endswith("c")
if prefix_a or prefix_A and suffix_c:
print("要查找的元素:%s" % S)
14.写代码，有如下列表，按照要求实现每一个功能
li = ["alex","eric","rain"]
计算列表长度并输出
li = ["alex","eric","rain"]
v = len(li)
print(v)
列表中追加元素 “seven”，并输出添加后的列表
li = ["alex","eric","rain"]
li.append("seven")
print(li)
请在列表的第 1 个位置插入元素 “Tony”，并输出添加后的列表
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li = ["alex","eric","rain"]
li.insert(0,"Tony")
print(li)
请修改列表第 2 个位置的元素为 “Kelly”，并输出修改后的列表
li = ["alex","eric","rain"]
li[1] = "Kelly"
print(li)
请删除列表中的元素 “eric”，并输出修改后的列表
li = ["alex","eric","rain"]
li.remove("eric")
print(li)
请删除列表中的第 2 个元素，并输出删除的元素的值和删除元素后的列表
li = ["alex","eric","rain"]
v = li.pop(1)
print(v,li)
请删除列表中的第 3 个元素，并输出删除元素后的列表
li = ["alex","eric","rain"]
li.pop(2)
print(li)
请删除列表中的第 2 至 4 个元素，并输出删除元素后的列表
li = ["alex","eric","rain","rain","rain"]
del li[1:4]
print(li)
请将列表所有的元素反转，并输出反转后的列表
li = ["alex","eric","rain"]
li.reverse()
print(li)
请使用 for、len、range 输出列表的索引
li = ["alex","eric","rain"]
for i in range(len(li)):
print(i)
请使用 enumrate 输出列表元素和序号（序号从 100 开始）
li = ["alex","eric","rain"]
for i,v in enumerate(li,100):
print(i,v)
请使用 for 循环输出列表的所有元素
li = ["alex","eric","rain"]
for i in li:
print(i)
15.写代码，有如下列表，请按照功能要求实现每一个功能
li = ["hello", "seven", ["mon", ["h", "kelly"], "all"], 123, 446]
请根据索引输出“Kelly”
li = ["hello", "seven", ["mon", ["h", "kelly"], "all"], 123, 446]
print(li[2][1][1])
请使用索引找到”all”元素并将其修改为“ALL”，如：li[0][1][9]...
li = ["hello", "seven", ["mon", ["h", "kelly"], "all"], 123, 446]
li[2][2] = "ALL"
print(li)
16.写代码，有如下元祖，请按照功能要求实现每一个功能
tu = ("alex","eric","rain")
计算元组长度并输出
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tu = ("alex","eric","rain")
v = len(tu)
print(v)
获取元组的第 2 个元素，并输出
tu = ("alex","eric","rain")
v = tu[1]
print(v)
获取元组的第 1‐2 个元素，并输出
tu = ("alex","eric","rain")
v = tu[0:2]
print(v)
请使用 for 输出元组的元素
tu = ("alex","eric","rain")
for i in tu:
print(i)
请使用 for、len、range 输出元组的索引
for i in range(len(tu)):
print(i)
请使用 enumrate 输出元祖元素和序号（序号从 10 开始）
tu = ("alex","eric","rain")
for i,v in enumerate(tu,10):
print(i,v)
17.有如下变量，请实现要求的功能
tu = ("alex", [11, 22, {"k1": "v1", "k2": ["age", "name"], "k3": (11,22,33)}, 44])
- 讲述元祖的特性
元组的一级元素不可被修改增加删除，有序，可迭代，可切片，可索引，可转换为列表。
- 请问 tu 变量中的第一个元素 “alex” 是否可被修改？
不可被修改
- 请问 tu 变量中的”k2″对应的值是什么类型？是否可以被修改？如果可以，请在其中添加一个元素 “Seven”
tu = ("alex", [11, 22, {"k1": "v1", "k2": ["age", "name"], "k3": (11,22,33)}, 44])
v = tu[1][2]["k2"]
v.append("Seven")
print(tu)
- 请问 tu 变量中的”k3″对应的值是什么类型？是否可以被修改？如果可以，请在其中添加一个元素 “Seven”
k3对应的是元组,不可修改
18.现有商品列表如下：
products = [ ["iphone8",6888], ["MacPro", 14800], ["小米6",2499], ["coffee",31],["book",80],["Nike shoes",799]]
请打印出这样的格式：
-----------商品信息 ------------
0. iphone8 6888
1. MacPro 14800
2. 小米6 2499
3. coffee 31
4. book 80
5. Nike shoes 799
products = [ ["iphone8",6888], ["MacPro", 14800], ["小米6",2499], ["coffee",31],["book",80],["Nike shoes",799]]
print("商品信息".center(28,"-"))
for index,product in enumerate(products):
print("%s.%s %s" %(index,product[0],product[1]))
# print("{0}.{1} {2}".format(index,product[0],product[1]))
19.利用上题中的列表，写一个循环，不断的问用户想买什么，用户选择一个商品标号，就把对应的商品添加到购物车里，最终用户输入q退出时，打印购物车里的商品列表。
products = [ ["iphone8",6888], ["MacPro", 14800], ["小米6",2499], ["coffee",31],["book",80],["Nike shoes",799]]
shopping_cart = [] # 定义一个空的购物车
exit_flag = False
# while True:
while not exit_flag:
print("商品信息".center(28, "-"))
for index,product in enumerate(products):
print("%s. %s %d" % (index,product[0],product[1]))
product_choice = input("
请输入商品标号：
")
if product_choice.isdigit(): #判断输入的字符串是否只包含数字
product_choice = int(product_choice) # 字符串转成整型
if product_choice >= 0 and product_choice < len(products):
shopping_cart.append(products[product_choice][0]) #增加到购物车列表
print("
商品 %s 已添加到购物车
" % (products[product_choice][0]))
else:
print("商品标号有误,请重新输入")
elif product_choice == "q":
if len(shopping_cart) > 0:
print("
您添加到购物车的商品如下：
")
for index,product_cart in enumerate(shopping_cart):
print("%s. %s" % (index,product_cart))
else:
print("
您的购物车为空！
")
# break
exit_flag = True #为真时候结束循环
