python怎么判断是不是中文字符?

python中可以通过判断字符的unicode值来判断字符是不是中文字符。

def is_chinese(uchar):
        """判断一个unicode是否是汉字"""
        if uchar >= u'/u4e00' and uchar<=u'/u9fa5':
                return True
        else:
                return False
                
def is_number(uchar):
        """判断一个unicode是否是数字"""
        if uchar >= u'/u0030' and uchar<=u'/u0039':
                return True
        else:
                return False
                
def is_alphabet(uchar):
        """判断一个unicode是否是英文字母"""
        if (uchar >= u'/u0041' and uchar<=u'/u005a') or (uchar >= u'/u0061' and uchar<=u'/u007a'):
                return True
        else:
                return False

def is_other(uchar):
        """判断是否非汉字,数字和英文字符"""
        if not (is_chinese(uchar) or is_number(uchar) or is_alphabet(uchar)):
                return True
        else:
                return False

def B2Q(uchar):
        """半角转全角"""
        inside_code=ord(uchar)
        if inside_code<0x0020 or inside_code>0x7e:      #不是半角字符就返回原来的字符
                return uchar
        if inside_code==0x0020: #除了空格其他的全角半角的公式为:半角=全角-0xfee0
                inside_code=0x3000
        else:
                inside_code+=0xfee0
        return unichr(inside_code)

def Q2B(uchar):
        """全角转半角"""
        inside_code=ord(uchar)
        if inside_code==0x3000:
                inside_code=0x0020
        else:
                inside_code-=0xfee0
        if inside_code<0x0020 or inside_code>0x7e:      #转完之后不是半角字符返回原来的字符
                return uchar
        return unichr(inside_code)

def stringQ2B(ustring):

        """把字符串全角转半角"""

        return "".join([Q2B(uchar) for uchar in ustring])

def uniform(ustring):

        """格式化字符串,完成全角转半角,大写转小写的工作"""

        return stringQ2B(ustring).lower()

def string2List(ustring):
        """将ustring按照中文,字母,数字分开"""
        retList=[]
        utmp=[]
        for uchar in ustring:
                if is_other(uchar):
                        if len(utmp)==0:
                                continue
                        else:
                                retList.append("".join(utmp))
                                utmp=[]
                else:
                        utmp.append(uchar)
        if len(utmp)!=0:
                retList.append("".join(utmp))
        return retList

if __name__=="__main__":
        #test Q2B and B2Q
        for i in range(0x0020,0x007F):
                print Q2B(B2Q(unichr(i))),B2Q(unichr(i))

        #test uniform

        ustring=u'中国 人名a高频A'

        ustring=uniform(ustring)

        ret=string2List(ustring)

        print ret

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来源:PY学习网:原文地址:https://www.py.cn/article.html

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