用几十行代码实现python中英文分词
说到分词大家肯定一般认为是很高深的技术,但是今天作者用短短几十行代码就搞定了,感叹python很强大啊!作者也很强大。不过这个只是正向最大匹配,没有机器学习能力
注意:使用前先要下载搜狗词库
# -*- coding:utf-8 -*- #写了一个简单的支持中文的正向最大匹配的机械分词,其它不用解释了,就几十行代码 #附:搜狗词库下载地址:http://vdisk.weibo.com/s/7RlE5 import string __dict = {} def load_dict(dict_file="words.dic"): #加载词库,把词库加载成一个key为首字符,value为相关词的列表的字典 words = [unicode(line, "utf-8").split() for line in open(dict_file)] for word_len, word in words: first_char = word[0] __dict.setdefault(first_char, []) __dict[first_char].append(word) #按词的长度倒序排列 for first_char, words in __dict.items(): __dict[first_char] = sorted(words, key=lambda x:len(x), reverse=True) def __match_ascii(i, input): #返回连续的英文字母,数字,符号 result = "" for i in range(i, len(input)): if not input[i] in string.ascii_letters: break result += input[i] return result def __match_word(first_char, i , input): #根据当前位置进行分词,ascii的直接读取连续字符,中文的读取词库 if not __dict.has_key(first_char): if first_char in string.ascii_letters: return __match_ascii(i, input) return first_char words = __dict[first_char] for word in words: if input[i:i+len(word)] == word: return word return first_char def tokenize(input): #对input进行分词,input必须是uncode编码 if not input: return [] tokens = [] i = 0 while i < len(input): first_char = input[i] matched_word = __match_word(first_char, i, input) tokens.append(matched_word) i += len(matched_word) return tokens if __name__ == "__main__": def get_test_text(): import urllib2 url = "http://news.baidu.com/n?cmd=4&class=rolling&pn=1&from=tab&sub=0" text = urllib2.urlopen(url).read() return unicode(text, "gbk") def load_dict_test(): load_dict() for first_char, words in __dict.items(): print "%s:%s" % (first_char, " ".join(words)) def tokenize_test(text): load_dict() tokens = tokenize(text) for token in tokens: print token tokenize_test(unicode(u"美丽的花园里有各种各样的小动物")) tokenize_test(get_test_text())
我也学习啦~~~
来源:PY学习网:原文地址:https://www.py.cn/article.html